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Sagot :
The inequality to represent the perimeter of the triangle is given by (2n + 3) + (2n + 2) + n ≤ 30
- The solution to the inequality is n ≤ 5
- The largest possible lengths of the sides is 13 cm
Inequality to represent the perimeter of a triangle
- Perimeter of the triangle = not more than 30 cm
- Side a = (2n + 3)cm
- Side b = (2n + 2) cm
- Side c = n cm
Side a + side b + side c ≤ perimeter of the triangle
(2n + 3) + (2n + 2) + n ≤ 30
- open parenthesis
2n + 3 + 2n + 2 + n ≤ 30
5n + 5 ≤ 30
substract 5 from both sides
5n ≤ 30 - 5
5n ≤ 25
- divide both sides by 5
n ≤ 25/5
n ≤ 5 cm
The largest possible lengths of the sides is:
Side a = (2n + 3)cm
= 2(5) + 3
= 10 + 3
= 13 cm
Side b = (2n + 2) cm
= 2(5) + 2
= 10 + 2
= 12 cm
Side c = n cm
= 5 cm
So therefore, the largest possible length of the triangle is 13 cm
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