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a) complete the table, left to right
(-2, -1) (-1, 1) (0, 3) (1, 5) (2, 7) (3, 9)
the first thing I did was fill in my y intercept from my equation which is 3, in the box below x = 0.
Second I see my slope or rate is 2, (the coefficient next to the x) so my y or output value is + 2 for every x input.
b) Last step is to graph, attached.
a) complete the table, left to right
(-2, -1) (-1, 1) (0, 3) (1, 5) (2, 7) (3, 9)
the first thing I did was fill in my y intercept from my equation which is 3, in the box below x = 0.
Second I see my slope or rate is 2, (the coefficient next to the x) so my y or output value is + 2 for every x input.
b) Last step is to graph, attached.
Answer:
[tex]\large\begin{array}{|c|c|c|c|c|c|c|}\cline{1-7}x&-2&-1&0&1&2&3\\\cline{1-7}y&-1&1&3&5&7&9\\\cline{1-7}\end{array}[/tex]
See attachment for the graph of the equation.
Step-by-step explanation:
Given equation:
[tex]y=2x+3[/tex]
To complete the table of values for the given equation, substitute the values of x into the equation and solve for y:
[tex]\begin{aligned}x=-2 \implies y&=2(-2)+3\\&=-4+3\\&=-1\end{aligned}[/tex]
[tex]\begin{aligned}x=0 \implies y&=2(0)+3\\&=0+3\\&=3\end{aligned}[/tex]
[tex]\begin{aligned}x=1 \implies y&=2(1)+3\\&=2+3\\&=5\end{aligned}[/tex]
[tex]\begin{aligned}x=3 \implies y&=2(3)+3\\&=6+3\\&=9\end{aligned}[/tex]
Therefore, the completed table is:
[tex]\large\begin{array}{|c|c|c|c|c|c|c|}\cline{1-7}x&-2&-1&0&1&2&3\\\cline{1-7}y&-1&1&3&5&7&9\\\cline{1-7}\end{array}[/tex]
To draw the graph of the given equation, plot at least two ordered pairs from the table onto the given grid, then draw a straight line through them. (See attachment).
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