Answered

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We are given a solution of 12.0 M HCI and want
to prepare 300 mL of a 0.6 M solution. How
would we prepare it? (300 mL = 0.3 L)
M₁V1=M₂V2
M₁ = ? M
V₁ = ? L
M₂= ? M
V₂ = ? L
V₁ = ? L

Sagot :

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