Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.


Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $25 and same-day tickets cost $15. For one performance, there were 55 tickets sold in all, and the total amount paid for them was $1025. How many tickets of each type were sold?

Sagot :

sqdancefan

Answer:

  • advance: 20
  • same-day: 35

Step-by-step explanation:

You have tickets that sell for $25 and $15, and you sold 55 tickets for $1025. You want to know the number of each sold.

Setup

Let 'a' represent the number of advance tickets sold. Then 55-a is the number of same-day tickets sold. The total revenue is ...

  25a +15(55 -a) = 1025

Solution

  10a + 825 = 1025 . . . . . simplify

  10a = 200 . . . . . . . . . . subtract 825

  a = 20 . . . . . . . . . . . divide by 10; the number of advance tickets

  55 -20 = 35 . . . . the number of same-day tickets

20 advance tickets and 35 same-day tickets were sold.

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.