christianaumo5
Answered

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if x varies inversly as the square root of y varies and x=1 when y=4, find;
relationship between x and y
the value of x when y =9
the value of y when x=12​

Sagot :

sqdancefan

Answer:

  • x = 2/√y  or  y = 4/x²
  • x = 2/3
  • y = 1/36

Step-by-step explanation:

When x varies inversely as the square root of y, and x=1 when y=4, you want to find ...

  • the relationship between x and y
  • the value of x when y =9
  • the value of y when x=12​.

Inverse variation

The given relation can be written using a constant of proportionality as ...

  x = k/√y  . . . . x varies as the inverse of the square root of y

The value of k can be found from the given values for x and y:

  1 = k/√4 = k/2

  2 = k . . . . . . . . . multiply by 2

Relationship

The relationship between x and y can be written as ...

  x = 2/√y

Solving for y, it can also be written as ...

  y = 4/x²

For y = 9

The value of x is ...

  x = 2/√9

  x = 2/3

For x=12

The value of y is ...

  y = 4/12² = 4/144

  y = 1/36

View image sqdancefan
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