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Graph the line with slope 2/3 passing through the point (3,2)

Sagot :

apologiabiology
so the line is in slope intercept form
y=mx+b, m=slope and b=y intercept
we know the slope so just solve for b
y=2/3x+b
subsitute
3 for x and 2 for y
2=2/3(3)+b
2=2+b
subtract 2 from both sdies
0=b
so the equaiton is
y=2/3x+0 or just simply
y=2/3x
here is the graph
just input values for x and get y values exg
x=3 y=2
x=6 y=4
x=0 y=0
x=-3 y=-2
View image apologiabiology
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