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How to solve 0.5(5-7x)=8-(4x+6)

Sagot :

[tex]\frac { 1 }{ 2 } \left( 5-7x \right) =8-\left( 4x+6 \right) \\ \\ \frac { 1 }{ 2 } \left( 5-7x \right) =8-4x-6[/tex]

[tex]\\ \\ \frac { 1 }{ 2 } \left( 5-7x \right) =2-4x\\ \\ \frac { 1 }{ 2 } \left( 5-7x \right) =2\left( 1-2x \right) \\ \\ 2\cdot \frac { 1 }{ 2 } \left( 5-7x \right) =2\cdot 2\left( 1-2x \right)[/tex]

[tex]\\ \\ 5-7x=4\left( 1-2x \right) \\ \\ 5-7x=4-8x\\ \\ -7x+8x=4-5\\ \\ x=-1[/tex]
batsbud18

Hey! Just answering so the other guy can have brainiest! Hope this helped!

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