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Sagot :
[tex]Method\ \#1:\\\\\frac{7}{10}=0.7\\\\\frac{3}{4}=0.75\\\\0.7 < 0.75\ therefore\ bigger\ is\ \frac{3}{4}\\------------------------[/tex]
[tex]Method\ \#2\\\\Find\ LCD\ of\ \frac{7}{10}\ and\ \frac{3}{4}\to\ LCD(\frac{7}{10};\ \frac{3}{4})=20\\\\\frac{7}{10}=\frac{7\cdot2}{10\cdot2}=\frac{14}{20};\ \frac{3}{4}=\frac{3\cdot5}{4\cdot5}=\frac{15}{20}\\\\\frac{14}{20} < \frac{15}{20}\ therefore\ bigger\ is\ \frac{3}{4}[/tex]
[tex]Method\ \#2\\\\Find\ LCD\ of\ \frac{7}{10}\ and\ \frac{3}{4}\to\ LCD(\frac{7}{10};\ \frac{3}{4})=20\\\\\frac{7}{10}=\frac{7\cdot2}{10\cdot2}=\frac{14}{20};\ \frac{3}{4}=\frac{3\cdot5}{4\cdot5}=\frac{15}{20}\\\\\frac{14}{20} < \frac{15}{20}\ therefore\ bigger\ is\ \frac{3}{4}[/tex]
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