Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
[tex]2x+3y=-12 \\
\underline{-2x+y=4 \ \ \ } \\
3y+y=-12+4 \\
4y=-8 \\
y=-2 \\ \\
2x+3y=-12 \\
2x+3 \times (-2)=-12 \\
2x-6=-12 \\
2x=-12+6 \\
2x=-6 \\
x=-3 \\ \\
\boxed{(x,y)=(-3,-2)}[/tex]
2x + 3y = -12
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.