Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
[tex]2x+3y=-12 \\
\underline{-2x+y=4 \ \ \ } \\
3y+y=-12+4 \\
4y=-8 \\
y=-2 \\ \\
2x+3y=-12 \\
2x+3 \times (-2)=-12 \\
2x-6=-12 \\
2x=-12+6 \\
2x=-6 \\
x=-3 \\ \\
\boxed{(x,y)=(-3,-2)}[/tex]
2x + 3y = -12
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.