Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
[tex]2x+3y=-12 \\
\underline{-2x+y=4 \ \ \ } \\
3y+y=-12+4 \\
4y=-8 \\
y=-2 \\ \\
2x+3y=-12 \\
2x+3 \times (-2)=-12 \\
2x-6=-12 \\
2x=-12+6 \\
2x=-6 \\
x=-3 \\ \\
\boxed{(x,y)=(-3,-2)}[/tex]
2x + 3y = -12
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.