Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

solve each system using elimination.
2x+3y=-12
-2x+y=4

Sagot :

naǫ
[tex]2x+3y=-12 \\ \underline{-2x+y=4 \ \ \ } \\ 3y+y=-12+4 \\ 4y=-8 \\ y=-2 \\ \\ 2x+3y=-12 \\ 2x+3 \times (-2)=-12 \\ 2x-6=-12 \\ 2x=-12+6 \\ 2x=-6 \\ x=-3 \\ \\ \boxed{(x,y)=(-3,-2)}[/tex]
xXxGirxXx
2x + 3y = -12
-2x + y = 4

First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest

Multiply the bottom equation by a -3

2x + 3y = -12
6x - 3y = -12

Then, you practically add them together (the y's will cancel out)

8x = -24

Divide both sides by 8

x = -3

Then, plug your x into either equation

-2 (-3) + y = 4

6 + y = 4

Subtract your 6 over to the 4

y = -2

(You can check this buy plugging in both your x and y into both equations)

(x, y)
(-3, -2)
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.