Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

carnen enters a painting contest. the contest rules say that all paintings must be rectangular with an area no graether than 3003.04cm2carmens painting is 16 cm wide. whar is the grather length the painting can have and still have an area within the contest rules?

Sagot :

ezwhiz
This problem requires the knowledge of the area of a rectangle.
The area of any rectangle is Area=Length•Width.
Since the maximum area is 3003.04 cm² and the width is 16 cm, you the area and length into this equation.
3003.04=16•Width
To solve for your width you must divide 3003.04 by 16.
3003.04÷16=187.69
So the greatest possible width of Carmen's painting is 187.69.
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.