Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

carnen enters a painting contest. the contest rules say that all paintings must be rectangular with an area no graether than 3003.04cm2carmens painting is 16 cm wide. whar is the grather length the painting can have and still have an area within the contest rules?

Sagot :

ezwhiz
This problem requires the knowledge of the area of a rectangle.
The area of any rectangle is Area=Length•Width.
Since the maximum area is 3003.04 cm² and the width is 16 cm, you the area and length into this equation.
3003.04=16•Width
To solve for your width you must divide 3003.04 by 16.
3003.04÷16=187.69
So the greatest possible width of Carmen's painting is 187.69.