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Sagot :
Taking x as the number to be found,
x=32a+30=58b+44 where a and b are the quotients you get on dividing x by 32 and 58.
Simplifying this equation you get 16a+15=29b+22
16a= (16+13)b+22-15 or 16a=16b+13b+7
16(a-b)=13b+7
Now I have to find a value for b where 13b+7 is divisible by 16. The least common multiple of these numbers can be found by going through the multiplication tables of 13 and 16 and 13x13+7=176, while 16x11 is also 176.
Now that the value of b is found to be 13, we can substitute it in our first equation, x=58b+44=58x13+44=798.
Now find the least common multiple of 58 and 32
LCM (n,m)=nm/GCD (n,m) where GCD is the greatest common divisor of n and m
LCM (58, 32)=58x32/2 as 2 is the GCD of 58 and 32
LCM (58, 32)= 1856/2= 928
Add this LCM to the previous answer, ie, 798 to get the next answer in the series. 798+928=1726
Add the LCM again to the last answer to get the final answer, that is less than 3000=1726+928=2654
x=32a+30=58b+44 where a and b are the quotients you get on dividing x by 32 and 58.
Simplifying this equation you get 16a+15=29b+22
16a= (16+13)b+22-15 or 16a=16b+13b+7
16(a-b)=13b+7
Now I have to find a value for b where 13b+7 is divisible by 16. The least common multiple of these numbers can be found by going through the multiplication tables of 13 and 16 and 13x13+7=176, while 16x11 is also 176.
Now that the value of b is found to be 13, we can substitute it in our first equation, x=58b+44=58x13+44=798.
Now find the least common multiple of 58 and 32
LCM (n,m)=nm/GCD (n,m) where GCD is the greatest common divisor of n and m
LCM (58, 32)=58x32/2 as 2 is the GCD of 58 and 32
LCM (58, 32)= 1856/2= 928
Add this LCM to the previous answer, ie, 798 to get the next answer in the series. 798+928=1726
Add the LCM again to the last answer to get the final answer, that is less than 3000=1726+928=2654
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