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4x+15y=13
3x+5y=16
solving systems by elimination

Sagot :

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4x+15y=13 (1)
3x+5y=16  (2)
(2) * 3 --> 9x+15y=48 becomes (3)
(3) - (1) 
5x=35
x=7
sub x =7 into (1)
4(7)+15y=13
28+15y=13 
-28         -28
15y= -15
y= -15/15
y= -1 

therefore x=7 and y= -1
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