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How do you do 5ln x= 35....?

Sagot :

AL2006

That's going to depend a lot on what you want to "do" to it.

I'm going to assume that you want to find a number for 'x' that makes
the whole equation a true statement.  Here's how I would do it:

                                  5 ln(x) = 35

Divide each side by  5:  ln(x) = 35/5
                                      ln(x)  =  7

Raise 'e' to the power of each side:    e^[ ln(x) ] = e⁷

But  e^[ ln(x) ] is just 'x'.  So x = e⁷ = 1,096.633... (rounded)

That's the only number you can write in place of 'x'
and make the original equation true.


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