Answered

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five times a number decreased by eight is at most ten more than twice the number

Sagot :

[tex]5n-8 \leq 2n+10 \\ 5n-8+8 \leq 2n+10+8 \\ 5n \leq 2n+18 \\ 5n-2n \leq 2n+18-2n \\ 3n \leq 18 \\ \frac{3n}{3} \leq \frac{18}{3} \\ n \leq 6 [/tex]
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