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Sodium metal reacts with aluminum chloride to produce sodium chloride and aluminum. The balanced reaction is: 3 Na(s) + AlCl3(aq) --> 3 NaCl(aq) + Al(s).  How many moles of aluminum metal could you get when 12.0 grams of sodium react with excess aluminum chloride?

Sagot :

First convert 12.0g of Na to moles using the grams to moles conversation and you get about .5219 moles (I didn't use significant figures). Divide that number by 3 because that is the coefficient of Na and you will get about .17398 moles, which is how many moles are in 1. Since Al has a coefficient of 1, .17398 woild be your final answer
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