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Stuck on question 1, can anyone help???

Stuck On Question 1 Can Anyone Help class=

Sagot :

AL2006

'A' is the square root of 25. That's 5, so take A=5 with you
as you go to the next step.

B is A³.   A³ means (A x A x A).  We know that 'A' is 5, so 'B' is (5x 5 x 5) = 125 .
Take B=125 with you to the next step.

'C' is  B - 25.  We know that  'B'  is 125.  So  C = (125 - 25) = 100 .
Take  C=100  with you to the next step.

'D' is the square root of  'C'.  We know that C=100, so  D = √100 .
The square root of 100 is 10, so  D=10.
Take  D=10  with you to the next step .

'E' is  D+39.  We know that  D=10.  So  E=(10+39) = 49 .
Take  E=49 with you to the last step.

'F' is the square root of 'E'.  We know that E=49.


apologiabiology
so square root of 25=a
a could be 5
cube of a=b
5^3=125=b
125-25=c=100
c=100
squareroot of 100=d=10
10+39=e=49
square root of 49=7
F=7


a=5
b=125
c=100
d=10
e=49
f=7
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