Answered

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can someone help me with number 19 please?

Can Someone Help Me With Number 19 Please class=

Sagot :

AL2006

I think I can.
Let's do it together:

Let's call the number of buses 'B', and the number of vans 'V'.
(Pretty clever so far, don't you think ?)

OK. What do we know ?

-- Each bus holds 51 passengers.  The number of passengers in 'B' buses is 51B.

-- A van holds 10 passengers.  The number of passengers in 'V' vans is 10V.

-- The total number of passengers ... (51B + 10V) ... is 142.

-- The total number of vehicles ... (B + V) ... is 6, because there are 6 drivers.

Can you make a system of equations out of that information yet ?
How about this:

     51B + 10V = 142
         B  +    V =     6

I really think you can handle it from here.
=======================================

Multiply the 2nd equation by 10 :

     51B + 10V = 142
     10B + 10V =   60

Subtract the 2nd equation from the 1st one:

       41B        =  82

Divide each side by 41:    B = 2 buses

2 buses . . . . 2 drivers . . . . 2 x 51 = 102 passengers

4 vans . . . . . 4 drivers . . . . . 4 x 10 =  40 passengers

6 vehicles . . . 6 drivers . . . . . 102 + 40 = 142 passengers


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