Answered

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Given: Prove: CDEF is a parallelogram
Statements
13
L
1. 2. FC II DE
3. 4.mk FCE+M LDCE = MLFCD
5. m² FEC + m 6. MLFCE=M² DEC
7. m² FCD = m 8. m² DEC+MLDCE = MLDEF
9. m² FEC+ m²DEC=McDEC+ m²DCE 9
10. ML FEC = MCDCE
10
ASA
CPCTC
[ Alt. Int. Conu.
112 - Opps sides are =
11. CD 11 FE
12. CDEF is a parallelogram

Sagot :

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