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Sagot :
The total number of possible strings that can be chosen is 4^13, since there are 13 characters and 4 possible choices for each character, b, c, d). Now, we need to determine the number of strings that contain at least one pair of adjacent characters that are the same in this probability.
To do this, we'll consider each letter in the string and calculate the number of possible strings that contain at least one pair of adjacent characters that are the same for that letter. For the first letter in the string, there are 4 strings that contain at least one pair of adjacent characters that are the same (aa, bb, cc, dd).For the second letter in the string, there are 4 strings that contain at least one pair of adjacent characters that are the same (ab, be, cd, dc).For the third letter in the string, there are 4 strings that contain at least one pair of adjacent characters that are the same (ac, bd, ca, db.).For the fourth letter in the string, there are 4 strings that contain at least one pair of adjacent characters that are the same (ad, bc, da, cb).
We can continue this process for each letter
We get probability as 83.3%
Learn more about probability here
https://brainly.com/question/12226830
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