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a .50 kilogram puck is sliding on a horizontal shuffle board court is slowed to rest by a frictional force of 1.2 newtons what is the coeffivent of kinetic friction betweej the puck and the surface of the shuffle board court

Sagot :

The puck's kinetic friction coefficient only with shuffleboard court's surface is 0.24.

How does kinetic friction work?

It is known as a force that exists between moving surfaces as kinetic friction. A force that operates in the opposing direction to the motion of a body on the surface is felt. The percentage of kinetic friction of the two materials will determine the size of the force.

Briefing:

Given  ,The mass of puck is, m = 0.50 kg.

The magnitude of frictional force is, f = 1.2 N.

The force which tends to oppose the motion between an object and the surface is known as frictional force. And its value is,

F= μ × mg

here,   is the coefficient of kinetic friction between the puck and the surface of the shuffleboard court.

Solving as ,

1.2 = u × 0.50 × 9.8

 μ =  [tex]\frac{1.2}{0.50 . 9.8}[/tex]

 μ = 0.24

Thus, we can conclude that the coefficient of kinetic friction between the puck and the surface of the shuffleboard court is 0.24.

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