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in the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. suppose the background signal level is 13 mv, the signal is 91 mv with no attenuator and is 25 mv with an attenuator in place. calculate pt/pi including the background correction. round your answer to 3 digits after the decimal point.

Sagot :

15.38 % is pt/pi including the background correction.

What is the definition of an amplitude simple?

The greatest deviation from equilibrium of a point on either a vibrating body or wave in terms of displacement or distance traveled. It is similar to the half-length of the vibration path.

Briefing :

Background [tex]=13mv[/tex]

corrected signal [tex]= 91mv - 13 mv = 78mv[/tex]

with attenuator[tex]=25mv - 13mv = 12 mv[/tex]

[tex]\frac{P_{t} }{P_{i} } = \frac{12}{78} . 100[/tex]

[tex]= 15.38 %[/tex] %

Therefore , the pt/pi is 15.38 %

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