Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

amc 12a 2014] let a < b < c be three integers such that a, b, c is an arithmetic progression and a, c, b is a geometric progression. what is the smallest possible value of c?

Sagot :

The smallest possible value of c is 1 in this case.

If the integer a, b and c are in arithmetic progression.

Then we can write,

b = (a+c)/2

If the integer a, b and c are in geometric progression,

Then, we can write,

b = √(ac)

Now, we can write,

a+b = 2√(ac)

Squaring both sides,

a²+c²+2ac = 4ac

(a-c)² = 0

So,

a = c.

If a = c.

Then,

b = (a+a)/2

b = a

So, a = b = c.

Smallest possible positive integer is 1.

So, the smallest possible value of c is 1.

To know more about Arithmetic progression, visit,

https://brainly.com/question/6561461

#SPJ4

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.