Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
A whopping 32% of people have the heterozygous malaria resistance gene.
A hereditary condition known as sickle-cell anemia is autosomal recessive. Blood cells in homozygous recessive individuals have the sickle shape. Contrarily, the sickle cell trait is exclusively carried by heterozygous people. The carriers do not experience malaria because they are immune to the parasites that cause it.
If 4% of people in an African population are born with sickle cell disease, therefore the population's proportion of heterozygous people who are malaria resistant will be:
Equilibrium is the Hardy-Weinberg formula.
    p² + 2pq + q² = 1 Â
p = frequency of the population's dominant allele
q is the population's prevalence of the recessive allele.
p² = the proportion of homozygous dominant people
q² is the proportion of homozygous recessive people.
2pq = the proportion of heterozygous people
Given that the square root of the homozygous recessive allele for this gene (q2) is 0.2 (20%) and the homozygous allele (q2) is 4%, or 0.04, then p should be 1-0.2 = 0.8 (20%).
Therefore, the percentage of heterozygous people is 2pq.2 (0.8 x 0.2) = 0.32 (32%).
Learn more about Hardy-Weinberg equilibrium at
https://brainly.com/question/16823644?referrer=searchResults
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.