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Sagot :
Answer: The mass when it returns to equilibrium position V=d√(k/m)
Reason:
The mass of the spring is set into simple harmonic motion at the equilibrium position A mass attached to a spring is free to oscillate, with angular velocity ω, in a horizontal plane without friction or damping. It is pulled to a distance X0 and pushed towards the centre with a velocity V0 at time t = 0.
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