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Sagot :
The probability that the average length of a randomly selected bundle of steel rods is 155.8 then P = 0.174 cm
Given sample size 'n' = 30 steel rods
Mean of the Population = 155.1 cm
Standard deviation of the Population = 1.4 cm
Given x⁻ be the random variable of Normal distribution
Let x₁⁻ = 155.8cm
The probability that the average length of a randomly selected bundle of steel rods is 155.8-cm.
P(x⁻₁ < x⁻ <x⁻₂) = P(Z₁ < Z <Z₂)
= P(Z <Z₂) - P(Z<Z₁)
= 0.5 +A(1.629) - (0.5 +A(0.7541)
= A(1.629) - A(0.7541)
= 0.4474 - 0.2734
= 0.1
The probability that the average length of a randomly selected bundle of steel rods is 155.8 cm = 0.174
learn more about of probability here
https://brainly.com/question/16752717
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