in a p -n junction, the n-doping nd is doubled. how do the following change if everything else remains unchanged? indicate only increase or decrease. (a) junction capacitance (b) built-in potential (c) breakdown voltage (d) ohmic losses

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01-12-2022
Engineering

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in a p -n junction, the n-doping nd is doubled. how do the following change if everything else remains unchanged? indicate only increase or decrease. (a) junction capacitance (b) built-in potential (c) breakdown voltage (d) ohmic losses

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kumarravichandra kumarravichandra · Answer 1 · 2022-12-05T11:25:48-05:00

In a p-n junction, option c is accurate because the is double. the values below change if everything else stays the same and they only indicate a rise or fall in breakdown voltage.

Breakdown voltage It is the voltage at which current in a forward biased PN junction begins to flow or increases. When reverse voltage is present, junctions break down and reverse current increases quickly. The depletion layer's width narrows. The depletion layer becomes wider. A diode's breakdown voltage specifies the highest reverse voltage that can be used without exponentially increasing the leakage current in the diode. A diode won't necessarily be destroyed if its breakdown voltage is exceeded, but it will be if its current capacity is. To create an ionization path through the dielectric, the open gap voltage must increase before current can flow.

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