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susan invests 2 times as much money at 8 % as she does at 4 % . if her total interest after 1 year is $ 1200 , how much does she have invested at each rate?

Sagot :

Susan invested $6000 at 4% and $12000 at 8% to gain a total interest of $1200 in a period of 1 year

Simple Interest is calculated by multiplying the principal amount by the rate of interest and the time in years for which it is invested divided by 100.

Let her principal for 4% be x then for 8% it is 2x.

Time is 1 year

Hence,

Interest for 4% = x*4*1/100

= 0.04x

Interest for 8% = 2x*8*1/100

= 0.16x

Interest for 4% + Interest for 8% = 1200

0.20x = 1200

x = $6000

The amount invested at 4% is $6000 and the amount invested at 8% is $12000

Learn more about simple interests:

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