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Sagot :
The volume of Hydrogen gas is 3.88L
The mass of aluminium = 3.12 g
Molar mass of aluminium = 26.98 g/mol
Calculating the number of moles -
Number of moles = Given Mass/Molar Mass
= 3.12/26.98
= 0.116 mol
Thus,
By Stoichiometry of the reaction:
Two moles of aluminium produce three moles of hydrogen gas. Thus, 0.116 moles of aluminium will produce -
= 3/2 × 0.116
= 0.173 mol
Calculating the volume of hydrogen gas produced by the equation -
PV = nRT
V = nRT/P
Using the standard temperature of gas = 273K
= 0.173 × 0.0821 × 273K/1 atm
= 3.88
Read more about Stoichiometry on:
https://brainly.com/question/22685837
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