Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The volume of Hydrogen gas is 3.88L
The mass of aluminium = 3.12 g
Molar mass of aluminium = 26.98 g/mol
Calculating the number of moles -
Number of moles = Given Mass/Molar Mass
= 3.12/26.98
= 0.116 mol
Thus,
By Stoichiometry of the reaction:
Two moles of aluminium produce three moles of hydrogen gas. Thus, 0.116 moles of aluminium will produce -
= 3/2 × 0.116
= 0.173 mol
Calculating the volume of hydrogen gas produced by the equation -
PV = nRT
V = nRT/P
Using the standard temperature of gas = 273K
= 0.173 × 0.0821 × 273K/1 atm
= 3.88
Read more about Stoichiometry on:
https://brainly.com/question/22685837
#SPJ4
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
