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a femur 18 inches long is placed in traction with an elevation of 6.2 inches. what is the angle of elevation of the femur?

Sagot :

The angle of elevation of the femur is 71°.

The angle of elevation:

The angle is formed by the line of sight and the horizontal plane for an object above the horizontal.

Here we have to find the angle of elevation of the femur.

Data given:

length of femur = 18 inches

elevated = 6.2 inches

Formula to calculate the angle of elevation:

Tangent of the angle of elevation = height of the object/distance from the object

tan Ф = 18/ 6.2

tan Ф = 2.903

Ф = [tex]tan^{-1}[/tex]( 2.903)

   = 71°

Therefore the angle of elevation is 71°.

To know more about the angle of elevation refer to the link given below:

https://brainly.com/question/88158

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