Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

day weight (ounces) monday 23 22 23 24 tuesday 23 21 19 21 wednesday 20 19 20 21 thursday 18 19 20 19 friday 18 20 22 20 what is the mean of the sampling distribution of sample means when this process is in control?

Sagot :

contexto1024

The value of the required mean of the sampling distribution of sample means is approx. 21 ounces when this process is in control.

Sample mean: The arithmetic mean of the values of the variables in the sample. If the samples are drawn from probability distributions with a common expected value, the sample mean is an estimate of that expected value.

Sample means for all days using formula,

Monday = (23+22+23+24)/4 = 23

Tuesday = (23+21+19+21)/4 = 21

Wednesday = (20+19+20+21)/4 = 20

Thursday = (18+19+20+19)/4 = 19

Friday = (18+20+22+20)/4 = 20

We have to calculate the mean of sampling distribution of sample means.

Mean of the sampling distribution of sample means = Sum of sample means of all days / Number of days

= (23+21+20+19+20)/5

= 20.6 = 21 ounces

Hence, the required mean is approx. 21 ounces.

To learn more about Sampling distribution of sample means , refer:

https://brainly.com/question/26952915

#SPJ4

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.