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on a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. if 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?

Sagot :

The percent of the ship's passengers held round-trip tickets is 50/100 = 50%.

Since the number of passengers on the ship is immaterial, let the number of passengers on the ship be 100 for convenience.  

Let x be the number of passengers that held round-trip tickets.  

Then, since 20 percent of the passengers held a round-trip ticket and took their cars aboard the ship, 0.20(100) = 20 passengers held round-trip tickets and took their cars aboard the ship.  

The remaining passengers with round-trip tickets did not take their cars aboard, and they represent 0.6x (that is, 60 percent of the passengers with round-trip tickets).  

Thus, 0.6x + 20 = x, from which it follows that 20 = 0.4x, and so x = 50.  

The percent of passengers with round-trip tickets is, then, 50/100 = 50%

A roundtrip flight is a flight itinerary that includes one flight to a vacation spot and some other flight lower back from that destination, which include flying from NYC to Paris after which Paris lowers back to NYC. The direction might also include layovers or connections, however, the beginning and endpoint are equal.

Ask the enterprise to alter the round-trip ticket for one-way usage. although airways exercise a varying degree of flexibility, many airlines will regulate a round-ride fare to permit one-manner use, though a few airlines might also charge a penalty or charge for this provider.

also known as “return air tickets,” round-journey tickets are flights from and again to the equal place beginning. A one-manner price tag, then again, simplest lets you to fly your destination, now not back from it.

To learn more about round-trip visit here:

brainly.com/question/18915875  

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