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when 70.0 g of li3n(s) reacts with excess h2(g), 8.0 g of linh2 (s) is produced. the percent yield is closest to

Sagot :

The percent yield is closest to 17%

How to calculate the percentage yield

The reaction between  Li3N(s) and LiH(s) is given as:

Li3N + 3H2 = 3LiH + NH3

Calculate the moles of Li3N

Moles = Mass/Molar mass

Moles = 70/35

Moles = 2 moles

From the reaction you can see that 1 mole of Li3N produce 3 moles of LiH, hence the moles of LiH is 6 moles

Determine the mass of LiH (theoretical yield)

Mass of LiH = 6 * 7.95

Mass of LiH = 47.7g

%yield = actual/theoretical * 100

%yield = 8/47.7 * 100

%yiels = 16.77%

Hence the percent yield is closest to 17%

Learn more on percent yield here:

brainly.com/question/25996347

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