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Sagot :
[tex]CaCl_{2}[/tex] is the substance that one would anticipate lowering water's freezing point the most.
This makes use of the freezing point depression theory. When dealing with this problem, we employ the equation shown below:
T = iKfm, which is rendered as follows in English:
Vant Hoff factor times molal freezing point depression constant * Solution molality equals the change in freezing point.
The quantity of molecules, not their composition, determines the freezing point depression because it is a colligative feature.
Now that we are certain that Kf and molality will remain constant, the Van't Hoff factor, also known as "i" is our sole remaining unknown.
The number of atoms that separate from each particular molecule is known as the Van't Hoff factor. The freezing point will be more depressed the greater the Van't Hoff factor.
NaCl will dissociate into Na+ and Cl-, therefore it has I = 2 CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has I = 3. Sugar (C12H22O11) has I = 1.
Choice B is the appropriate response as a result.
To learn more about freezing point, refer:-
https://brainly.com/question/13380426
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