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how many grams of aluminum can form by passing 353 c through an electrolytic cell containing a molten aluminum salt?

Sagot :

0.0329 grams of aluminum can form by passing 353 c through an electrolytic cell containing a molten aluminum salt

AL^3+ + 3A^-   = AL

3 moles of e- = 1 mole AL

3 faraday e- =  1 mole AL

3 * 96485  c = 1 mole AL

1 c = (1 / 3*96485)*27 g

353c = 353*27 / 3*96485 g

        = 0.0329 g of AL

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