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suppose a random variable has population standard deviation 29.5. what is the margin of error corresponding to the 95% confidence interval for a sample mean constructed from a sample of size 53?

Sagot :

The margin of error corresponding to the 95% confidence interval for a sample mean constructed from a sample of size 53 is 7.94.

Margin of error is defined as the degree of the sampling errors in statistics. It can be calculated using the formula below.

MOE = z x (SD / √n)

where MOE = margin of error

z = found by using a z-score table

SD = sample standard deviation = 29.5

n = sample size = 53

At 95% confidence level, the area in each tail of the standard normal curve is 2.5, and the cumulative area up to the second tail is 97.5.

(100 - 95) / 2 = 2.5

100 - 2.5 = 97.5

Find 0.975 in the z-table to get the value of z.

At p = 0.975, z = 1.96

Plug in the values to the formula and solve for the margin of error.

MOE = z x (SD / √n)

MOE = 1.96 x (29.5/√53)

MOE = 7.94

Learn more about margin of error here: brainly.com/question/10218601

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