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you have a set of points with a y:x constant ratio of 3:7. what is the equation of the line passing through these points?

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The equation of the line passing through these points i.e (7,3 ) and (14,6) is

y = (3/7) x or 3x - 7y = 0 ,

Which is linear equation of two variables.

A linear equation is an algebraic equation of the form y = mx + b , with only one constant and one first-order (linear) term, m is the slope and b is the y-intercept.

We have given that,

the ratio of y and x is y : x = 3 : 7

So the ratio of x and y can be expressed as ,

x : y = 7 : 3 ( reverse order)

So let's consider two points as

(x₁, y₁)=(7 , 3) and (x₂, y₂) = (14 , 6)

The equation of the line passing through these points will be,

( y - y₁ )/ (y₂ - y₁) = (x - x₁)/(x₂ - x₁)

=> (y - 3)/(6-3) = (x - 7)/(14 - 7)

=> (y - 3)/3 = (x - 7)/7

=> 7(y - 3) = 3( x - 7)

=> 7y - 21 = 3x - 21

=> 7y = 3x

=> y = (3/7) x

Hence, y = (3/7) x is required equation of line.

To learn more about Equation of line, refer:

https://brainly.com/question/18831322

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