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Sagot :
The location of its image in rel-ation to the mirror is -2.5 m
Given that, an object placed 45.0 cm from a concave mirror having the focal length of 15.0 cm and height of image is 5.0 cm.
We have to find the image distance (v) from the mirror and height of the image (h).
From above data we have, focal length (f) of concave mirror is -15 cm, object distance (u) is -45 cm and height of image (h) is 5 cm.
Now, Using Mirror Formula
1/f = 1/v + 1/u
Where f is focal length, v is image distance from the mirror and u is object distance from the mirror (concave).
The known values in the above formula to find the value of 'v' i.e. image distance from the mirror.
1/(-15) = 1/v + 1/(-45)
-1/15 = 1/v1 - /45
-1/15 + 1/45 = 1/v
(-3+1)/45 = 1/v
-2/45 = 1/v
-45/2 = v
-22.5 = v
Therefore, the image distance from the concave mirror is -22.5 cm.
Now,
m = -v/u = h/h•
Replace the values,
-(-22.5)/(-45) = h/5
-0.5 = h/5
-2.5 = h
Hence, the location of its image in rel-ation to the mirror is -2.5 m
Learn more about Concave mirror here:
https://brainly.com/question/26505785
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