Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
With a pressure drop of 120 kpa/m, glycerin at 380 c flows through a horizontal pipe with a 9 mm diameter. The Reynolds number is 3.807 after the discharge.
pressure drop=32μVL/D²
120*10³=32*0.95*V*1/(9*10⁻³)²
Velocity V=0.329 m/sec
discharge =AV
=π(9*10⁻³)²/4*0.319
pressure drop=2.02*10⁻⁵ m³
then,
Reynolds number=VD/γ
=δVD/μ
1.26*10³*0.319*9*10⁻³/0.95
=3.807
By measuring the proportion of inertial and viscous forces, the Reynolds number aids in the prediction of flow patterns in various fluid flow scenarios. Laminar flow typically predominates in low Reynolds numbers flows while turbulent flow predominates in high Reynolds numbers flows.
Learn more about Reynolds number here:
https://brainly.com/question/12977616
#SPJ4
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
