Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

calculate the pressure due to the ocean, in atmospheres, at the bottom of this trench. given that its depth is 11.0 km and assuming the density of seawater is a constant 1.025 x 103 kg/m? all the way down

Sagot :

Let's first create our working equation. Everyone is aware that pressure is a force applied to a specific area of space. That would be P = F/A in an equation. According to Newton's Second Law of Motion, force equals mass times gravity, or F = mg. So, we can change the first equation to read P = mg/A by substituting F.

Now, the force that a fluid applies to a surface may also be used to calculate pressure. The volume of this fluid can be calculated. The density parameter, p = m/V, is used to relate volume and mass. Volume is the product of the cross-sectional area and the height, to further simplify things in terms of height. So, V = A*h. Following that, the working equation will be derived to be

P = pgh

The pressure that a fluid exerts over a specified height is referred to as hydrostatic pressure. We then locate the density of seawater data from the literature. According to research, saltwater has a density between 1,020 and 1,030 kg/m3. Let's stick with 1.020 kg/m3. Making the units consistent while substituting the values:

P = (1,020 kg/m³) (9.81 m/s2)(11 km)*(1,000 m/1km)

P = 110,068,200 Pa or 110.07 MPa

Learn more about Pressure here:

https://brainly.com/question/28012687

#SPJ4