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Sagot :
The probability that [tex]\bar{x}[/tex] < 1.57 for the given mean, standard deviation , and samples is equal to 0.0162.
As given in the question,
Normal distribution with mean 'μ' = 1.59 millimeters
Standard deviation 'σ' = 0.042 millimeters
Sample size 'n' = 20
standard error = σ /√n
= 0.042 / √20
= 0.00933
Probability that [tex]\bar{x}[/tex] < 1.57 is
X = 1.57
s = 0.0093
P( X < 1.57)
= P[ (X -μ)/s < ( 1.57 - 1.59)/ 0.0093]
= P ( z < -2.14 )
Using z - table p value is
= 0.01617
= 0.0162
Therefore, the probability for the [tex]\bar{x}[/tex] < 1.57 is equal to 0.0162.
The complete question is :
A factory makes components used in jet engines, including reinforced steel washers. the washers are required to have a very precise thickness. the thickness of the washers follow a normal distribution with mean 1.59 millimeters and standard deviation 0.042 millimeters. a technician randomly samples n = 20 washers and calculates the mean of their thicknesses, which is x¯. what is the probability that x¯<1.57?
Learn more about probability here
brainly.com/question/11234923
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