isochoric process is a process in which the gas keeps its volume constant. in an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 j. has energy been absorbed or released in the process?

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01-12-2022
Physics

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isochoric process is a process in which the gas keeps its volume constant. in an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 j. has energy been absorbed or released in the process?

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Tutorconsortium709 Tutorconsortium709 · Answer 1 · 2022-12-06T07:45:33-05:00

Isochoric (constant volume) Thermal (internal) energy change = - 50 J Negative sign signifies a loss or decrease in internal energy.

Since the volume is constant in an isochoric process and we know that work done is directly proportional to the change in volume, work done for a constant volume process is zero, we can use the first law of thermodynamics to calculate the following:

Where dQ is the heat transported and dU is the change in internal energy, dQ = dU + dW

dW stands for the amount of work completed.

Since there was no work done, this means:

dQ =dU

dQ=-50 Joules

Thus, during the procedure, the heat exchanged with the gas was - 50 joules (the negative sign merely denotes that the heat was extracted from the gas).

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