Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
If each side of a square is increasing at a rate of 7 cm/s, then the rate of increasing the area of the the square when the area of the square is 64 cm square is 112 centimeter square per second
The rate of change of length with respect to the time = 7 cm per second
That is
dl / dt = 7 cm per second
The area of the square = l^2
Where l is the length of the square
The rate of change area with respect to the time is
dA / dt = 2l dl/dt
The area is given that 64 centimeter square and the side will be 8 cm
Substitute the values in the equation
dA / dt = 2 × 8 × 7
= 112 centimeter square per second
Therefore, the rate of increasing the area is 112 centimeter square per second
Learn more about area here
brainly.com/question/874186
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
