At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
0.823 grams oxygen could be produced from 2.45 g of potassium dioxide and 4.62 grams of carbon dioxide.
Definition of Chemical reaction
Chemical reactions happen absolutely everywhere in our daily life. While we sometimes associate chemical reactions with only the sterile environment of test tubes and laboratories, nothing is farther from the truth. In fact, a wide range of transformations are creating a dizzying and almost incomprehensible series of new matter and energy changes in our world every second of every day.
Moles KO₂ = 2.41g/(71.1g/mole) = 0.034 moles
Moles CO₂ = 4.62g/(44g/mole) = 0.105 moles
4KO₂ + 2CO₂ → 2K₂CO₃ + 3O₂
The reaction requires twice as many moles of KO₂ than moles of CO₂. That means 0.105 mole of CO₂ would consume 0.034 moles of KO₂. But there is only have 0.034 moles of KO₂, so the limiting reagent is KO₂.
There are 3 moles of O₂ produced for every 2 moles of CO₂ consumed. In this case we'll assume all of the KO₂ reacts, so that should result in (3/4) × (0.034moles) = 0.025 moles of O₂ .
To get the mass, 0.025 mole × (32g/mole) = 0.823 grams O₂
Hence, 0.823 grams O₂ could be produced from 2.45 g of KO₂ and 4.62 grams o.f CO₂.
Learn more about amount of oxygen produced from the link given below.
https://brainly.com/question/13920330
#SPJ4
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.