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Sagot :
The emf is doubled
The change in electric potential energy of a charge is equal to the work done by a battery to carry a unit charge across the battery from one terminal to the other, hence it may be expressed as
w=qΔV
where
The charge is q.
ΔV is the difference in potential that the charge has traveled through.
The potential difference is equal to the battery's emf because the charge is flowing through the battery e, which means.
W=qe (1)
We are informed in this issue that the battery's output has increased, so
w'=2W
We can see from eq. (1) that the battery's emf is proportional to the work performed; as a result, when the work doubles, so does the battery's emf.
What is potential difference?
The difference in charge carriers energy between two places in a circuit is known as the potential difference.
To know more about potential difference visit
https://brainly.com/question/21808222
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