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Sagot :
The probability that a car chosen to random will need:
A) no repairs: 72%
B) No more than one repairs: 89%
C) some repairs: 11%
The total amount of cars that will need some type of repair is 28%; 17% will need to be repaired once + 7% will need to be repaired twice + 4% will need to be repaired more than two times.
The amount of cars that wouldn´t need any type of repairs is the total amount of cars minus the percentage that need some type of repair:
100% - 28% = 72%.
The amount of cars that will need no repairs or only one repair is the total amount of cars minus the percentage that need more than one of repair:
100% - (7% + 4%) = 89%.
The amount of cars that need some repairs is the sum of those cars that need two repairs plus those that need three or more repairs:
7% + 4% = 11%
Learn more about Probability:
https://brainly.com/question/16484393
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