Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
A seismic station 4,000 kilometers distant noted the earthquake. The time gap between the arrival of the P-wave and the arrival of the S-wave was 320 seconds.
Please refer to the attached picture below. The graph indicates that the P-wave will reach the seismic station in 7 minutes. P-wave extrapolation stops at a vertical time scale cutoff of 7 minutes. At 12 min. 20 sec., the S-wave will reach the seismic station.
On the vertical scale, one minute is split into three segments. Thus, each segment will last 20 seconds.
So, travel time difference = S wave arrival - P wave arrival
= 12 minutes 20 seconds - 7 minutes
= 5 minutes 20 seconds
We know that 1 minute = 60 seconds
So, 5 minutes = 5 × 60
= 300 seconds
Consequently, the distance between the arrival of P wave and the arrival of S-wave = 300 seconds + 20 seconds
= 320 seconds
To learn more about earthquake
https://brainly.com/question/29500066
#SPJ4
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.