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Sagot :
The quadratic equation 15[tex]x^{2}[/tex]-22x -7 = 0 has solution x = 1.7355 or -0.26886
In algebra, a quadratic equation (from Latin quadratus 'square') is any equation that can be rearranged in standard form as
a[tex]x^{2}[/tex] + bx + c =0
where x represents an unknown value, and a, b, and c represent known numbers. One supposes generally that a ≠ 0; those equations with a = 0 are considered degenerate because the equation then becomes linear or even simpler. The numbers a, b, and c are the coefficients of the equation and may be distinguished by calling them, respectively, the quadratic coefficient, the linear coefficient and the constant or free term.
The values of x that satisfy the equation are called solutions of the equation, and roots or zeros of the expression on its left-hand side. A quadratic equation has at most two solutions. If there is only one solution, one says that it is a double root. If all the coefficients are real numbers, there are either two real solutions, or a single real double root, or two complex solutions that are complex conjugates of each other. A quadratic equation always has two roots, if complex roots are included; and a double root is counted for two. A quadratic equation can be factored into an equivalent equation
given that
5(x-1)3x = 7(x+1)
15[tex]x^{2}[/tex]-15x = 7x +7
15[tex]x^{2}[/tex]-22x -7 = 0
x = -b ± [tex]\sqrt{b^{2}-4ac }[/tex]/2a
x = -(-22) ± [tex]\sqrt{(-22)-4(15)(-7)}[/tex] /2(15)
x = 1.7355 or -0.26886
To learn more about quadratic equation:
https://brainly.com/question/17177510
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