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at a particular pressure and temperature, it takes 4.55 min for a 1.5-l sample of he to effuse through a porous membrane. how long does it take for 1.5 l of f2 to effuse under the same conditions?

Sagot :

Time required to diffuse the F2 gas under the same conditions pressure and temperature with same volume is equal to 14 mins( approximately).

As given in the question,

Time taken by 1.5L sample of He gas to diffuse = 4.55 min.

Molar mass of He gas = 4g

Volume of He gas = 1.5L

Volume of F2 gas = 1.5L

Molar mass of F2 = 38gm

Formula of Rate of diffusion is given by :

Rate of diffusion of He / Rate of diffusion of F2

= √Molar mass of F2 / √Molar mass of He

Now,

Rate of He = Volume of He / time taken

                  = 1.5 / 4.55  

Rate of F2 = [ ( Rate of He ) ×√ Molar mass of He ] / √ Molar mass of F2

                 = ( 1.5 / 4.55 ) × ( √4 / √38)

                 = 3 / 28.028

                 = 0.107 L / min

Time of F2 = Volume of F2 / Rate of F2

                  = 1.5 / 0.107

                  = 14.02 minutes

                  ≈ 14 minutes.

Therefore, the time taken by F2 to diffuse under the same condition of He is equal to 14 minutes.

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