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a student of mass 50kg decides to go on the ride. the coefficient of static friction between the student and wall is 0.8. if the diameter of the ride is 10m, what is the maximum period of the ride's rotation that will keep the student pinned to the wall once the floor drops?

Sagot :

Ride's rotation that will keep the student pinned to the wall once the floor drops is  3.97 sec.

What is rotation?

rotation is a type of trasfermation that takes each point in a figure and rotates its a certain number.

Mass of student = 50 kg

Coefficient of static friction  \mu = 0.8 μ=0.8

Ride diameter  d = 10 m d=10m

Ride radius  r = \frac{d}{2} = 5 m r= 2d

=5m

Acceleration due to gravity  g = 10 m/s^2 g=10m/s

2

Maximum period of ride's rotation =

Formula:   \text{ Maximum period } = \500{\text{ Circumference }}{\10m/s{ Velocity }}  Maximum period =

Velocity

Circumference                

Step 1: Calculating the static frictional force and normal force

This frictional force will be equal to the student's weight to

 find out what minimum static frictional force is required

Hence, maximum period of ride's rotation  P = 3.97 P=3.97 sec

to know more about rotation click-

https://brainly.com/question/28134390

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