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Sagot :
14.61 g of sodium chloride is dissolved in water to make 500 ml of solution. (show work) a. what is the mass/volume %? b. what is the molarity of this solution? 0.499 (approx)
Mass of sodium chloride, msolute=14.61 g (given)
Volume of solution,v solution=500 ml=0.5 litres (given)
a. Mass/volume % is ratio of mass of solute in grams and volume of solution in ml multiplied from 100%
Mass/volume%=(msolute/vsolution)*100%
=(14.61/500)*100%
Mass/volume%=2.928%
b. Mass of sodium is 23 and chlorine is 35.5
Molecular mass of sodium chloride ie NaCl=23*1+35.5*1=58.5
Number of moles of NaCl is found by dividing mass of NaCl in grams by molecular mass of NaCl,
Number of moles of NaCl,nsolute=14.61/58.5
Molarity of the solution is found by dividing number of moles of solute ie sodium chloride (NaCl) from volume of solution in litres,
Thus,
Molarity of solution=nsolute/vsolution
=(14.61/58.5) / 0.5
=0.499 (approx)
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